What is the answer to (x^2+x-12)/(x-3)=x+4 ?

The answer to (x^2+x-12)/(x-3)=x+4 is x\ne 3

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(x^2+x-12)/(x-3)=x+4

\frac{x ^{2} + x - 12}{x - 3} = x + 4

x \neq = 3

Solution steps

\frac{x ^{2} + x - 12}{x - 3} = x + 4

Simplify

\frac{x ^{2} + x - 12}{x - 3} : x + 4

x + 4 = x + 4

Both sides are equal

True for all x

Verify Solutions

Find undefined (singularity) points:

x = 3

Since the equation is undefined for:

3

x \neq = 3

\frac{x + 3}{x} = 2

103 = \frac{( 2 x - 3 )}{10 - 6 x}

\frac{0.49}{x} = \frac{x}{0.64}

\frac{2}{x} = \frac{7}{9}

\frac{32}{x} = 4

What is the answer to (x^2+x-12)/(x-3)=x+4 ?
The answer to (x^2+x-12)/(x-3)=x+4 is x\ne 3
Solve for x: (x^2+x-12)/(x-3)=x+4
The solution is x\ne 3