What is the answer to 6-5/(y+2)= 4/(y-1) ?

The answer to 6-5/(y+2)= 4/(y-1) is y=(1+sqrt(41))/4 ,y=(1-sqrt(41))/4

Solve for y: 6-5/(y+2)= 4/(y-1)

The solution is y=(1+sqrt(41))/4 ,y=(1-sqrt(41))/4

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6 - \frac{5}{y + 2} = \frac{4}{y - 1}

y = \frac{1 + 41}{4}, y = \frac{1 - 41}{4}

Decimal Notation

y = 1.85078 \dots, y = - 1.35078 \dots

Solution steps

6 - \frac{5}{y + 2} = \frac{4}{y - 1}

Multiply by LCM

6 (y + 2) (y - 1) - 5 (y - 1) = 4 (y + 2)

Solve

6 (y + 2) (y - 1) - 5 (y - 1) = 4 (y + 2) : y = \frac{1 + 41}{4}, y = \frac{1 - 41}{4}

y = \frac{1 + 41}{4}, y = \frac{1 - 41}{4}

Verify Solutions

Find undefined (singularity) points:

y = - 2, y = 1

Combine undefined points with solutions:

y = \frac{1 + 41}{4}, y = \frac{1 - 41}{4}

x + \frac{1}{x} = 92

149.122 = \frac{100 - 150}{x}

\frac{3 x}{x + 3} = 9 - \frac{9}{x + 3}

\frac{5}{x} = \frac{1}{3}

\frac{x - 2}{x - 1} = \frac{5}{4}

What is the answer to 6-5/(y+2)= 4/(y-1) ?
The answer to 6-5/(y+2)= 4/(y-1) is y=(1+sqrt(41))/4 ,y=(1-sqrt(41))/4
Solve for y: 6-5/(y+2)= 4/(y-1)
The solution is y=(1+sqrt(41))/4 ,y=(1-sqrt(41))/4