What is the answer to x^{-2}+8x^{-1}+7=0 ?

The answer to x^{-2}+8x^{-1}+7=0 is x=-1/7 ,x=-1

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x^{-2}+8x^{-1}+7=0

x^{- 2} + 8 x^{- 1} + 7 = 0

x = - \frac{1}{7}, x = - 1

Decimal Notation

x = - 0.14285 \dots, x = - 1

Solution steps

x^{- 2} + 8 x^{- 1} + 7 = 0

Refine

\frac{1}{x ^{2}} + \frac{8}{x} + 7 = 0

Multiply by LCM

1 + 8 x + 7 x^{2} = 0

Solve

1 + 8 x + 7 x^{2} = 0 : x = - \frac{1}{7}, x = - 1

x = - \frac{1}{7}, x = - 1

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = - \frac{1}{7}, x = - 1

\frac{2 x + 1}{x - 3} = 0

\frac{2 x + 3}{x - 2} = 9

x, \frac{x + y}{x} = y

\frac{0.24}{a} = \frac{6}{x}

\frac{x ^{2} - 4}{x - 2} = 0

What is the answer to x^{-2}+8x^{-1}+7=0 ?
The answer to x^{-2}+8x^{-1}+7=0 is x=-1/7 ,x=-1
Solve for x: x^{-2}+8x^{-1}+7=0
The solution is x=-1/7 ,x=-1