What is the answer to (3x^2+2x)/(5x^2-3)=0 ?

The answer to (3x^2+2x)/(5x^2-3)=0 is x=0,x=-2/3

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(3x^2+2x)/(5x^2-3)=0

\frac{3 x ^{2} + 2 x}{5 x ^{2} - 3} = 0

x = 0, x = - \frac{2}{3}

Decimal Notation

x = 0, x = - 0.66666 \dots

Solution steps

\frac{3 x ^{2} + 2 x}{5 x ^{2} - 3} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

3 x^{2} + 2 x = 0

Solve

3 x^{2} + 2 x = 0 : x = 0, x = - \frac{2}{3}

x = 0, x = - \frac{2}{3}

Verify Solutions

Find undefined (singularity) points:

x = \frac{3}{5}, x = - \frac{3}{5}

Combine undefined points with solutions:

x = 0, x = - \frac{2}{3}

\frac{3}{3 x - 2} = \frac{14}{9 x - 6}

\frac{x - 3}{x} = \frac{x + 7}{x + 4}

\frac{4}{x - 4} = 7 + \frac{x}{x - 4}

- 3 = \frac{5 x}{x ^{2} - 4}

x \frac{a x + b}{c x + d} = 2

What is the answer to (3x^2+2x)/(5x^2-3)=0 ?
The answer to (3x^2+2x)/(5x^2-3)=0 is x=0,x=-2/3
Solve for x: (3x^2+2x)/(5x^2-3)=0
The solution is x=0,x=-2/3