What is the answer to j(x)= 1/(x+1) ?

The answer to j(x)= 1/(x+1) is x=(-j+sqrt(j^2+4j))/(2j),x=(-j-sqrt(j^2+4j))/(2j);\quad j\ne 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

j(x)= 1/(x+1)

j (x) = \frac{1}{x + 1}

x = \frac{- j + j ^{2} + 4 j}{2 j}, x = \frac{- j - j ^{2} + 4 j}{2 j}; j \neq = 0

Solution steps

j (x) = \frac{1}{x + 1}

Multiply both sides by

x + 1

j x (x + 1) = 1

Solve

j x (x + 1) = 1 : x = \frac{- j + j ^{2} + 4 j}{2 j}, x = \frac{- j - j ^{2} + 4 j}{2 j}; j \neq = 0

x = \frac{- j + j ^{2} + 4 j}{2 j}, x = \frac{- j - j ^{2} + 4 j}{2 j}; j \neq = 0

4 = \frac{8}{5 + z}

\frac{9 x}{x + 1} = 5 - \frac{9}{x + 1}

\frac{1}{x - 2} + 4 = \frac{17}{x - 2}

y + \frac{2}{y} = \frac{9}{2}

\frac{x ( x - 5 )}{x ^{2} - 9} = 1

What is the answer to j(x)= 1/(x+1) ?
The answer to j(x)= 1/(x+1) is x=(-j+sqrt(j^2+4j))/(2j),x=(-j-sqrt(j^2+4j))/(2j);\quad j\ne 0