What is the answer to (3x+5)/(2x+1)-2=3 ?

The answer to (3x+5)/(2x+1)-2=3 is x=0

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(3x+5)/(2x+1)-2=3

\frac{3 x + 5}{2 x + 1} - 2 = 3

x = 0

Solution steps

\frac{3 x + 5}{2 x + 1} - 2 = 3

Move

2

to the right side

\frac{3 x + 5}{2 x + 1} = 5

Multiply both sides by

2 x + 1

3 x + 5 = 5 (2 x + 1)

Expand

5 (2 x + 1) : 10 x + 5

3 x + 5 = 10 x + 5

Move

5

to the right side

3 x = 10 x

Move

10 x

to the left side

- 7 x = 0

Divide both sides by

- 7

x = 0

Verify Solutions

Find undefined (singularity) points:

x = - \frac{1}{2}

Combine undefined points with solutions:

x = 0

\frac{2 x}{x - 2} + \frac{2}{x} = 3

y, \frac{y}{y - 5} = 2 x

q, \frac{F}{q} + 2 q = 4 q

\frac{5}{x + 5} = \frac{15}{x + 7}

\frac{7}{x} - 3 = 0

What is the answer to (3x+5)/(2x+1)-2=3 ?
The answer to (3x+5)/(2x+1)-2=3 is x=0
Solve for x: (3x+5)/(2x+1)-2=3
The solution is x=0