What is the answer to x^{-2}+3x^{-1}-4=0 ?

The answer to x^{-2}+3x^{-1}-4=0 is x=-1/4 ,x=1

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x^{-2}+3x^{-1}-4=0

x^{- 2} + 3 x^{- 1} - 4 = 0

x = - \frac{1}{4}, x = 1

Decimal Notation

x = - 0.25, x = 1

Solution steps

x^{- 2} + 3 x^{- 1} - 4 = 0

Refine

\frac{1}{x ^{2}} + \frac{3}{x} - 4 = 0

Multiply by LCM

1 + 3 x - 4 x^{2} = 0

Solve

1 + 3 x - 4 x^{2} = 0 : x = - \frac{1}{4}, x = 1

x = - \frac{1}{4}, x = 1

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = - \frac{1}{4}, x = 1

\frac{3 x + 2}{x + 3} - 5 = 2

\frac{2 x - 9}{4 x} = 5

\frac{5}{x} = \frac{6}{5 x} + 1

\frac{4}{( x + 1 ) ^{3}} = 0

\frac{4}{x} - \frac{x}{8} = 0

What is the answer to x^{-2}+3x^{-1}-4=0 ?
The answer to x^{-2}+3x^{-1}-4=0 is x=-1/4 ,x=1
Solve for x: x^{-2}+3x^{-1}-4=0
The solution is x=-1/4 ,x=1