What is the answer to (b^2+3^1(-3))/b =3 ?

The answer to (b^2+3^1(-3))/b =3 is b=(3+3sqrt(5))/2 ,b=(3-3sqrt(5))/2

Solve for b: (b^2+3^1(-3))/b =3

The solution is b=(3+3sqrt(5))/2 ,b=(3-3sqrt(5))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{b ^{2} + 3 ^{1} ( - 3 )}{b} = 3

b = \frac{3 + 3 5}{2}, b = \frac{3 - 3 5}{2}

Decimal Notation

b = 4.85410 \dots, b = - 1.85410 \dots

Solution steps

\frac{b ^{2} + 3 ^{1} ( - 3 )}{b} = 3

Simplify

\frac{b ^{2} + 3 ^{1} ( - 3 )}{b} : \frac{b ^{2} - 3 ^{2}}{b}

\frac{b ^{2} - 3 ^{2}}{b} = 3

Multiply both sides by

b

b^{2} - 3^{2} = 3 b

Solve

b^{2} - 3^{2} = 3 b : b = \frac{3 + 3 5}{2}, b = \frac{3 - 3 5}{2}

b = \frac{3 + 3 5}{2}, b = \frac{3 - 3 5}{2}

Verify Solutions

Find undefined (singularity) points:

b = 0

Combine undefined points with solutions:

b = \frac{3 + 3 5}{2}, b = \frac{3 - 3 5}{2}

r, m = \frac{n - p}{r - 5}

\frac{10}{x - 5} = \frac{8}{x - 1}

2 - \frac{6}{x ^{2}} = \frac{1}{x}

\frac{2}{x + 2} + 5 = \frac{17}{x + 2}

x, x + \frac{1}{x} = 9

What is the answer to (b^2+3^1(-3))/b =3 ?
The answer to (b^2+3^1(-3))/b =3 is b=(3+3sqrt(5))/2 ,b=(3-3sqrt(5))/2
Solve for b: (b^2+3^1(-3))/b =3
The solution is b=(3+3sqrt(5))/2 ,b=(3-3sqrt(5))/2