What is the answer to 2/(x+3)-4/x =1 ?

The answer to 2/(x+3)-4/x =1 is x=-5/2+i(sqrt(23))/2 ,x=-5/2-i(sqrt(23))/2

Solve for x: 2/(x+3)-4/x =1

The solution is x=-5/2+i(sqrt(23))/2 ,x=-5/2-i(sqrt(23))/2

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\frac{2}{x + 3} - \frac{4}{x} = 1

x = - \frac{5}{2} + i \frac{23}{2}, x = - \frac{5}{2} - i \frac{23}{2}

Solution steps

\frac{2}{x + 3} - \frac{4}{x} = 1

Multiply by LCM

2 x - 4 (x + 3) = x (x + 3)

Solve

2 x - 4 (x + 3) = x (x + 3) : x = - \frac{5}{2} + i \frac{23}{2}, x = - \frac{5}{2} - i \frac{23}{2}

x = - \frac{5}{2} + i \frac{23}{2}, x = - \frac{5}{2} - i \frac{23}{2}

\frac{x ^{2}}{( 0.25 - x )} = 2

\frac{1.2}{x} = 3.75

x, s (x) = \frac{3 x}{x + 5}

t, P = \frac{e}{t}

\frac{k + 6}{4 - k} = \frac{2}{k - 4}

What is the answer to 2/(x+3)-4/x =1 ?
The answer to 2/(x+3)-4/x =1 is x=-5/2+i(sqrt(23))/2 ,x=-5/2-i(sqrt(23))/2
Solve for x: 2/(x+3)-4/x =1
The solution is x=-5/2+i(sqrt(23))/2 ,x=-5/2-i(sqrt(23))/2