What is the answer to (4x)/(2x-1)= 3/(2x+1) ?

The answer to (4x)/(2x-1)= 3/(2x+1) is x= 1/8+i(sqrt(23))/8 ,x= 1/8-i(sqrt(23))/8

Solve for x: (4x)/(2x-1)= 3/(2x+1)

The solution is x= 1/8+i(sqrt(23))/8 ,x= 1/8-i(sqrt(23))/8

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\frac{4 x}{2 x - 1} = \frac{3}{2 x + 1}

x = \frac{1}{8} + i \frac{23}{8}, x = \frac{1}{8} - i \frac{23}{8}

Solution steps

\frac{4 x}{2 x - 1} = \frac{3}{2 x + 1}

Cross multiply

4 x (2 x + 1) = (2 x - 1) \cdot 3

Solve

4 x (2 x + 1) = (2 x - 1) \cdot 3 : x = \frac{1}{8} + i \frac{23}{8}, x = \frac{1}{8} - i \frac{23}{8}

x = \frac{1}{8} + i \frac{23}{8}, x = \frac{1}{8} - i \frac{23}{8}

\frac{2}{3} = \frac{x - 1}{x}

\frac{x + 4}{2 - x} = 2

240 = \frac{( 240 ) ^{2}}{x}

\frac{10}{30} = \frac{6}{t}

\frac{2 m - 4}{5} = \frac{6}{m}

What is the answer to (4x)/(2x-1)= 3/(2x+1) ?
The answer to (4x)/(2x-1)= 3/(2x+1) is x= 1/8+i(sqrt(23))/8 ,x= 1/8-i(sqrt(23))/8
Solve for x: (4x)/(2x-1)= 3/(2x+1)
The solution is x= 1/8+i(sqrt(23))/8 ,x= 1/8-i(sqrt(23))/8