What are the solutions to the equation 5x(x-1)-2(2x^2-7x)=-8 ?

The solutions to the equation 5x(x-1)-2(2x^2-7x)=-8 are x=-1,x=-8

Find the zeros of 5x(x-1)-2(2x^2-7x)=-8

The zeros of 5x(x-1)-2(2x^2-7x)=-8 are x=-1,x=-8

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5 x (x - 1) - 2 (2 x^{2} - 7 x) = - 8

x = - 1, x = - 8

Solution steps

5 x (x - 1) - 2 (2 x^{2} - 7 x) = - 8

Expand

5 x (x - 1) - 2 (2 x^{2} - 7 x) : x^{2} + 9 x

x^{2} + 9 x = - 8

Move

8

to the left side

x^{2} + 9 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 8 = 7

x_{1, 2} = \frac{- 9 \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 9 + 7}{2 \cdot 1}, x_{2} = \frac{- 9 - 7}{2 \cdot 1}

x = \frac{- 9 + 7}{2 \cdot 1} : - 1

x = \frac{- 9 - 7}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = - 1, x = - 8

(x + 3) (3 x - 1) = - 4

6 x^{2} - 29 x + 35

- 4 ∣ x + 2 ∣ - 8 = - 56

n^{2} + 7 n + 15 = 5

1 - 5 (- 7 r + 5) \leq - 5 r + 5 - 4

What are the solutions to the equation 5x(x-1)-2(2x^2-7x)=-8 ?
The solutions to the equation 5x(x-1)-2(2x^2-7x)=-8 are x=-1,x=-8
Find the zeros of 5x(x-1)-2(2x^2-7x)=-8
The zeros of 5x(x-1)-2(2x^2-7x)=-8 are x=-1,x=-8