What is -x^2+4x-3>= 0 ?

The solution to -x^2+4x-3>= 0 is 1<= x<= 3

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-x^2+4x-3>= 0

- x^{2} + 4 x - 3 \geq 0

1 \leq x \leq 3

Interval Notation

[1, 3]

Solution steps

- x^{2} + 4 x - 3 \geq 0

Factor

- x^{2} + 4 x - 3 : - (x - 1) (x - 3)

- (x - 1) (x - 3) \geq 0

Multiply both sides by

- 1

(reverse the inequality)

(- (x - 1) (x - 3)) (- 1) \leq 0 \cdot (- 1)

Simplify

(x - 1) (x - 3) \leq 0

Identify the intervals

1 \leq x \leq 3

(1 - x) (2 + x) = 1

\frac{- 100}{- 100 - 3}

- 1 \leq m + 8

- 2 x < 12

3 s + 15 = 3 (s + 5)