What is the answer to (2x^2+5x-3)/(x+3)=7 ?

The answer to (2x^2+5x-3)/(x+3)=7 is x=4

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(2x^2+5x-3)/(x+3)=7

\frac{2 x ^{2} + 5 x - 3}{x + 3} = 7

x = 4

Solution steps

\frac{2 x ^{2} + 5 x - 3}{x + 3} = 7

Simplify

\frac{2 x ^{2} + 5 x - 3}{x + 3} : 2 x - 1

2 x - 1 = 7

Move

1

to the right side

2 x = 8

Divide both sides by

2

x = 4

Verify Solutions

Find undefined (singularity) points:

x = - 3

Combine undefined points with solutions:

x = 4

2^{- 5} = \frac{1}{x}

x^{2} + \frac{1}{x ^{2}} = 2

\frac{5}{x - 3} + 9 = 2

\frac{3}{5} + \frac{7}{x + 2} = 2

\frac{2}{3 ( 9 x + 6 )} = 6 x + 4

What is the answer to (2x^2+5x-3)/(x+3)=7 ?
The answer to (2x^2+5x-3)/(x+3)=7 is x=4
Solve for x: (2x^2+5x-3)/(x+3)=7
The solution is x=4