What is the answer to (x+1)/(x^2+1)=8 ?

The answer to (x+1)/(x^2+1)=8 is x= 1/16+i(sqrt(223))/(16),x= 1/16-i(sqrt(223))/(16)

Solve for x: (x+1)/(x^2+1)=8

The solution is x= 1/16+i(sqrt(223))/(16),x= 1/16-i(sqrt(223))/(16)

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\frac{x + 1}{x ^{2} + 1} = 8

x = \frac{1}{16} + i \frac{223}{16}, x = \frac{1}{16} - i \frac{223}{16}

Solution steps

\frac{x + 1}{x ^{2} + 1} = 8

Multiply both sides by

x^{2} + 1

x + 1 = 8 (x^{2} + 1)

Solve

x + 1 = 8 (x^{2} + 1) : x = \frac{1}{16} + i \frac{223}{16}, x = \frac{1}{16} - i \frac{223}{16}

x = \frac{1}{16} + i \frac{223}{16}, x = \frac{1}{16} - i \frac{223}{16}

\frac{x + 1}{6 x} = \frac{x - 3}{5 x}

0.05 = \frac{250}{x} \cdot 100

x, z = \frac{m y}{x}

b, d = \frac{c}{b}

\frac{y - 4}{1} = \frac{2}{y - 3}

What is the answer to (x+1)/(x^2+1)=8 ?
The answer to (x+1)/(x^2+1)=8 is x= 1/16+i(sqrt(223))/(16),x= 1/16-i(sqrt(223))/(16)
Solve for x: (x+1)/(x^2+1)=8
The solution is x= 1/16+i(sqrt(223))/(16),x= 1/16-i(sqrt(223))/(16)