What is the answer to 1/(y+1)+1/(y+2)=1 ?

The answer to 1/(y+1)+1/(y+2)=1 is y=(-1+sqrt(5))/2 ,y=(-1-sqrt(5))/2

Solve for y: 1/(y+1)+1/(y+2)=1

The solution is y=(-1+sqrt(5))/2 ,y=(-1-sqrt(5))/2

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\frac{1}{y + 1} + \frac{1}{y + 2} = 1

y = \frac{- 1 + 5}{2}, y = \frac{- 1 - 5}{2}

Decimal Notation

y = 0.61803 \dots, y = - 1.61803 \dots

Solution steps

\frac{1}{y + 1} + \frac{1}{y + 2} = 1

Multiply by LCM

2 y + 3 = (y + 1) (y + 2)

Solve

2 y + 3 = (y + 1) (y + 2) : y = \frac{- 1 + 5}{2}, y = \frac{- 1 - 5}{2}

y = \frac{- 1 + 5}{2}, y = \frac{- 1 - 5}{2}

Verify Solutions

Find undefined (singularity) points:

y = - 1, y = - 2

Combine undefined points with solutions:

y = \frac{- 1 + 5}{2}, y = \frac{- 1 - 5}{2}

\frac{3}{2 ( 2 x + 4 )} = x + 19

x, \frac{x}{1 - x} = e^{y}

\frac{4}{x + 3} = 0

\frac{10}{k} = \frac{8}{4}

x - \frac{1}{3} = 32 x^{- 2}

What is the answer to 1/(y+1)+1/(y+2)=1 ?
The answer to 1/(y+1)+1/(y+2)=1 is y=(-1+sqrt(5))/2 ,y=(-1-sqrt(5))/2
Solve for y: 1/(y+1)+1/(y+2)=1
The solution is y=(-1+sqrt(5))/2 ,y=(-1-sqrt(5))/2