What is the answer to 1/x+1/(x+1)=2 ?

The answer to 1/x+1/(x+1)=2 is x= 1/(sqrt(2)),x=-1/(sqrt(2))

Solve for x: 1/x+1/(x+1)=2

The solution is x= 1/(sqrt(2)),x=-1/(sqrt(2))

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\frac{1}{x} + \frac{1}{x + 1} = 2

x = \frac{1}{2}, x = - \frac{1}{2}

Decimal Notation

x = 0.70710 \dots, x = - 0.70710 \dots

Solution steps

\frac{1}{x} + \frac{1}{x + 1} = 2

Multiply by LCM

2 x + 1 = 2 x (x + 1)

Solve

2 x + 1 = 2 x (x + 1) : x = \frac{1}{2}, x = - \frac{1}{2}

x = \frac{1}{2}, x = - \frac{1}{2}

Verify Solutions

Find undefined (singularity) points:

x = 0, x = - 1

Combine undefined points with solutions:

x = \frac{1}{2}, x = - \frac{1}{2}

6 x + \frac{6}{x ^{3}} = 0

\frac{0.25}{3} = \frac{1.2}{a}

\frac{x}{x - 5} = \frac{5}{x - 5} + 6

\frac{2}{3} = \frac{9}{X}

(\frac{12}{x} + 1) (x - 3) = 9

What is the answer to 1/x+1/(x+1)=2 ?
The answer to 1/x+1/(x+1)=2 is x= 1/(sqrt(2)),x=-1/(sqrt(2))
Solve for x: 1/x+1/(x+1)=2
The solution is x= 1/(sqrt(2)),x=-1/(sqrt(2))