What is the answer to solvefor g,h=(g-3)/(g-2) ?

The answer to solvefor g,h=(g-3)/(g-2) is g=(-3+2h)/(h-1);\quad h\ne 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor g,h=(g-3)/(g-2)

solve for

g, h = \frac{g - 3}{g - 2}

g = \frac{- 3 + 2 h}{h - 1}; h \neq = 1

Solution steps

h = \frac{g - 3}{g - 2}

Multiply both sides by

g - 2

h (g - 2) = g - 3

Expand

h (g - 2) : g h - 2 h

g h - 2 h = g - 3

Move

2 h

to the right side

g h = g - 3 + 2 h

Move

g

to the left side

g h - g = - 3 + 2 h

Factor

g h - g : g (h - 1)

g (h - 1) = - 3 + 2 h

Divide both sides by

h - 1; h \neq = 1

g = \frac{- 3 + 2 h}{h - 1}; h \neq = 1

\frac{x - 7}{x - 4} = \frac{5}{x}

\frac{4 x}{x - 2} + 3 = 1

(12.2)^{2} = \frac{640}{m}

p, p^{- 1} + q^{- 1} = - 2

\frac{x + 3}{5 x - 2} = \frac{x}{x + 1}

What is the answer to solvefor g,h=(g-3)/(g-2) ?
The answer to solvefor g,h=(g-3)/(g-2) is g=(-3+2h)/(h-1);\quad h\ne 1