What is the answer to 2b^{-2}=7b^{-1}-3 ?

The answer to 2b^{-2}=7b^{-1}-3 is b= 1/3 ,b=2

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2b^{-2}=7b^{-1}-3

2 b^{- 2} = 7 b^{- 1} - 3

b = \frac{1}{3}, b = 2

Decimal Notation

b = 0.33333 \dots, b = 2

Solution steps

2 b^{- 2} = 7 b^{- 1} - 3

Refine

\frac{2}{b ^{2}} = \frac{7}{b} - 3

Multiply by LCM

2 = 7 b - 3 b^{2}

Solve

2 = 7 b - 3 b^{2} : b = \frac{1}{3}, b = 2

b = \frac{1}{3}, b = 2

Verify Solutions

Find undefined (singularity) points:

b = 0

Combine undefined points with solutions:

b = \frac{1}{3}, b = 2

b, P = \frac{n RT}{V - nb}

\frac{1}{5 a + 8} = 9

\frac{1}{x - 2} - 1 = \frac{4}{x - 2}

\frac{1}{x} = \frac{x + 1}{2}

\frac{2}{x - 2} = \frac{5}{x - 1}

What is the answer to 2b^{-2}=7b^{-1}-3 ?
The answer to 2b^{-2}=7b^{-1}-3 is b= 1/3 ,b=2
Solve for b: 2b^{-2}=7b^{-1}-3
The solution is b= 1/3 ,b=2