What is the answer to (2/(x+1)+2)^2-5=11 ?

The answer to (2/(x+1)+2)^2-5=11 is x=0,x=-4/3

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(2/(x+1)+2)^2-5=11

(\frac{2}{x + 1} + 2)^{2} - 5 = 11

x = 0, x = - \frac{4}{3}

Decimal Notation

x = 0, x = - 1.33333 \dots

Solution steps

(\frac{2}{x + 1} + 2)^{2} - 5 = 11

Move

5

to the right side

(\frac{2}{x + 1} + 2)^{2} = 16

Expand

(\frac{2}{x + 1} + 2)^{2} : \frac{8 x + 12}{x ^{2} + 2 x + 1} + 4

\frac{8 x + 12}{x ^{2} + 2 x + 1} + 4 = 16

Move

4

to the right side

\frac{8 x + 12}{x ^{2} + 2 x + 1} = 12

Multiply both sides by

x^{2} + 2 x + 1

8 x + 12 = 12 (x^{2} + 2 x + 1)

Solve

8 x + 12 = 12 (x^{2} + 2 x + 1) : x = 0, x = - \frac{4}{3}

x = 0, x = - \frac{4}{3}

Verify Solutions

Find undefined (singularity) points:

x = - 1

Combine undefined points with solutions:

x = 0, x = - \frac{4}{3}

\frac{12}{y - 1} = \frac{2}{3}

- \frac{2}{5 x} + \frac{3}{20 x} = 5

\frac{1}{x} + 2 = 0

9 \cdot \frac{1000}{1000 + x} = 2

\frac{2}{5 x} = 2

What is the answer to (2/(x+1)+2)^2-5=11 ?
The answer to (2/(x+1)+2)^2-5=11 is x=0,x=-4/3
Solve for x: (2/(x+1)+2)^2-5=11
The solution is x=0,x=-4/3