What is the answer to (-8x)/((x^2-4)^2)=0 ?

The answer to (-8x)/((x^2-4)^2)=0 is x=0

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(-8x)/((x^2-4)^2)=0

\frac{- 8 x}{( x ^{2} - 4 ) ^{2}} = 0

x = 0

Solution steps

\frac{- 8 x}{( x ^{2} - 4 ) ^{2}} = 0

Simplify

\frac{- 8 x}{( x ^{2} - 4 ) ^{2}} : - \frac{8 x}{( x ^{2} - 4 ) ^{2}}

- \frac{8 x}{( x ^{2} - 4 ) ^{2}} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

8 x = 0

Divide both sides by

8

x = 0

Verify Solutions

Find undefined (singularity) points:

x = 2, x = - 2

Combine undefined points with solutions:

x = 0

\frac{5 x - 1}{1 - 2 x} = - 6

\frac{1}{x} = \frac{3}{6}

\frac{5}{6} = \frac{5 x}{x + 60}

\frac{3}{4} = \frac{4}{x}

\frac{9}{x ^{2}} + \frac{5}{x} = 4

What is the answer to (-8x)/((x^2-4)^2)=0 ?
The answer to (-8x)/((x^2-4)^2)=0 is x=0
Solve for x: (-8x)/((x^2-4)^2)=0
The solution is x=0