What is the answer to (1-8x^3)/(x^2)=0 ?

The answer to (1-8x^3)/(x^2)=0 is x= 1/2 ,x=-1/4+(sqrt(3))/4 i,x=-1/4-(sqrt(3))/4 i

Solve for x: (1-8x^3)/(x^2)=0

The solution is x= 1/2 ,x=-1/4+(sqrt(3))/4 i,x=-1/4-(sqrt(3))/4 i

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\frac{1 - 8 x ^{3}}{x ^{2}} = 0

x = \frac{1}{2}, x = - \frac{1}{4} + \frac{3}{4} i, x = - \frac{1}{4} - \frac{3}{4} i

Solution steps

\frac{1 - 8 x ^{3}}{x ^{2}} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

1 - 8 x^{3} = 0

Solve

1 - 8 x^{3} = 0 : x = \frac{1}{2}, x = - \frac{1}{4} + \frac{3}{4} i, x = - \frac{1}{4} - \frac{3}{4} i

x = \frac{1}{2}, x = - \frac{1}{4} + \frac{3}{4} i, x = - \frac{1}{4} - \frac{3}{4} i

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = \frac{1}{2}, x = - \frac{1}{4} + \frac{3}{4} i, x = - \frac{1}{4} - \frac{3}{4} i

\frac{4 x}{x + 1} = 6 - \frac{4}{x + 1}

- \frac{1}{3 x} = \frac{1 - x}{3 x}

\frac{76 ( 1 - r )}{1 - r ^{3}} = 36

y, x = \frac{1}{( 1 - y )} - 1

3 x (x + 5) = - 5 x^{- 2} + 2

What is the answer to (1-8x^3)/(x^2)=0 ?
The answer to (1-8x^3)/(x^2)=0 is x= 1/2 ,x=-1/4+(sqrt(3))/4 i,x=-1/4-(sqrt(3))/4 i
Solve for x: (1-8x^3)/(x^2)=0
The solution is x= 1/2 ,x=-1/4+(sqrt(3))/4 i,x=-1/4-(sqrt(3))/4 i