What are the solutions to the equation (x+1)^2=81 ?

The solutions to the equation (x+1)^2=81 are x=8,x=-10

Find the zeros of (x+1)^2=81

The zeros of (x+1)^2=81 are x=8,x=-10

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(x + 1)^{2} = 81

x = 8, x = - 10

Solution steps

(x + 1)^{2} = 81

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = 81 : x = 8

Solve

x + 1 = - 81 : x = - 10

The solutions to the quadratic equation are:

x = 8, x = - 10

\frac{1}{7} x - 5 = 8

n^{2} - 24 n - 25

- \frac{8}{4}

3 x + 3 (x + y)

- 7 x - 8 = - 10 x + 4

What are the solutions to the equation (x+1)^2=81 ?
The solutions to the equation (x+1)^2=81 are x=8,x=-10
Find the zeros of (x+1)^2=81
The zeros of (x+1)^2=81 are x=8,x=-10