What is the answer to (x^2+12)/(x^2-2)=27 ?

The answer to (x^2+12)/(x^2-2)=27 is x=sqrt(33/13),x=-sqrt(33/13)

Solve for x: (x^2+12)/(x^2-2)=27

The solution is x=sqrt(33/13),x=-sqrt(33/13)

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\frac{x ^{2} + 12}{x ^{2} - 2} = 27

x = \frac{33}{13}, x = - \frac{33}{13}

Decimal Notation

x = 1.59325 \dots, x = - 1.59325 \dots

Solution steps

\frac{x ^{2} + 12}{x ^{2} - 2} = 27

Multiply both sides by

x^{2} - 2

x^{2} + 12 = 27 (x^{2} - 2)

Solve

x^{2} + 12 = 27 (x^{2} - 2) : x = \frac{33}{13}, x = - \frac{33}{13}

x = \frac{33}{13}, x = - \frac{33}{13}

Verify Solutions

Find undefined (singularity) points:

x = 2, x = - 2

Combine undefined points with solutions:

x = \frac{33}{13}, x = - \frac{33}{13}

\frac{7 x}{x + 1} = 2 - \frac{7}{x + 1}

x = 3 + \frac{10}{x}

\frac{5 x}{x ^{2} - 30} = 5

\frac{1}{3 - x} = 2 - \frac{5}{3 - x}

a, u = \frac{kb}{a}

What is the answer to (x^2+12)/(x^2-2)=27 ?
The answer to (x^2+12)/(x^2-2)=27 is x=sqrt(33/13),x=-sqrt(33/13)
Solve for x: (x^2+12)/(x^2-2)=27
The solution is x=sqrt(33/13),x=-sqrt(33/13)