What is the answer to (25dt)/(dt)+t=80e^{-0.04t} ?

The answer to (25dt)/(dt)+t=80e^{-0.04t} is t=(\W_{0}((16e)/5)-1)/(0.04)

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(25dt)/(dt)+t=80e^{-0.04t}

\frac{25 d t}{d t} + t = 80 e^{- 0.04 t}

t = \frac{W _{0} ( \frac{16 e}{5} ) - 1}{0.04}

Decimal Notation

t = 16.44280 \dots

Solution steps

\frac{25 d t}{d t} + t = 80 e^{- 0.04 t}

Refine

25 + t = \frac{80}{e ^{0.04 t}}

Multiply both sides by

e^{0.04 t}

25 e^{0.04 t} + t e^{0.04 t} = 80

Solve

25 e^{0.04 t} + t e^{0.04 t} = 80 : t = \frac{W _{0} ( \frac{16 e}{5} ) - 1}{0.04}

t = \frac{W _{0} ( \frac{16 e}{5} ) - 1}{0.04}

(\frac{2000}{X} + 2) (X + 50) = 3300

\frac{5}{6} = r - \frac{6}{r + 3}

\frac{r - 4}{5 r} = \frac{1}{5 r} + 1

\frac{26}{x} = - 13

\frac{x + 4}{x} = 81

What is the answer to (25dt)/(dt)+t=80e^{-0.04t} ?
The answer to (25dt)/(dt)+t=80e^{-0.04t} is t=(\W_{0}((16e)/5)-1)/(0.04)