What are the solutions to the equation 2x^2+4x=-2 ?

The solutions to the equation 2x^2+4x=-2 are x=-1

Find the zeros of 2x^2+4x=-2

The zeros of 2x^2+4x=-2 are x=-1

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2 x^{2} + 4 x = - 2

x = - 1

Solution steps

2 x^{2} + 4 x = - 2

Move

2

to the left side

2 x^{2} + 4 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 2 \cdot 2}{2 \cdot 2}

4^{2} - 4 \cdot 2 \cdot 2 = 0

x_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 2}

x = \frac{- 4}{2 \cdot 2}

\frac{- 4}{2 \cdot 2} = - 1

x = - 1

The solution to the quadratic equation is:

x = - 1

∣ x + 4 ∣ \geq 4

3 n^{2} + 11 n + 4 = 0

8 x^{2} = 10 x

\frac{60}{10}

x^{2} - 2 x - 9 > 6

What are the solutions to the equation 2x^2+4x=-2 ?
The solutions to the equation 2x^2+4x=-2 are x=-1
Find the zeros of 2x^2+4x=-2
The zeros of 2x^2+4x=-2 are x=-1