What is the answer to 3x+2=(2x^2-3x+2)/(x-2) ?

The answer to 3x+2=(2x^2-3x+2)/(x-2) is x=3,x=-2

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3x+2=(2x^2-3x+2)/(x-2)

3 x + 2 = \frac{2 x ^{2} - 3 x + 2}{x - 2}

x = 3, x = - 2

Solution steps

3 x + 2 = \frac{2 x ^{2} - 3 x + 2}{x - 2}

Multiply both sides by

x - 2

3 x (x - 2) + 2 (x - 2) = 2 x^{2} - 3 x + 2

Solve

3 x (x - 2) + 2 (x - 2) = 2 x^{2} - 3 x + 2 : x = 3, x = - 2

x = 3, x = - 2

Verify Solutions

Find undefined (singularity) points:

x = 2

Combine undefined points with solutions:

x = 3, x = - 2

5 = \frac{7}{x}

x, y = \frac{x}{1 + x}

5 = \frac{2}{5} - \frac{8}{x}

1 - \frac{2}{x} = \frac{3}{2 x - 5}

5 = \frac{2}{5} - \frac{8}{c}

What is the answer to 3x+2=(2x^2-3x+2)/(x-2) ?
The answer to 3x+2=(2x^2-3x+2)/(x-2) is x=3,x=-2
Solve for x: 3x+2=(2x^2-3x+2)/(x-2)
The solution is x=3,x=-2