What is the answer to 1/(x-1)-3=(x-1)^3-3 ?

The answer to 1/(x-1)-3=(x-1)^3-3 is x=2,x=0

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1/(x-1)-3=(x-1)^3-3

\frac{1}{x - 1} - 3 = (x - 1)^{3} - 3

x = 2, x = 0

Solution steps

\frac{1}{x - 1} - 3 = (x - 1)^{3} - 3

Add

3

to both sides

\frac{1}{x - 1} - 3 + 3 = (x - 1)^{3} - 3 + 3

Simplify

\frac{1}{x - 1} = (x - 1)^{3}

Multiply both sides by

x - 1

1 = (x - 1)^{4}

Solve

1 = (x - 1)^{4} : x = 2, x = 0

x = 2, x = 0

Verify Solutions

Find undefined (singularity) points:

x = 1

Combine undefined points with solutions:

x = 2, x = 0

\frac{12}{x + 1} = \frac{9}{x - 6}

- \frac{3}{x} + \frac{3}{8 x} = 21

\frac{7}{x} = \frac{11}{3 x} - 8

x, f = \frac{k}{x}

\frac{1}{x + 3} + 2 = \frac{11}{x + 3}

What is the answer to 1/(x-1)-3=(x-1)^3-3 ?
The answer to 1/(x-1)-3=(x-1)^3-3 is x=2,x=0
Solve for x: 1/(x-1)-3=(x-1)^3-3
The solution is x=2,x=0