What is the answer to 0=x-1/(x^2) ?

The answer to 0=x-1/(x^2) is x=1,x=-1/2+(sqrt(3))/2 i,x=-1/2-(sqrt(3))/2 i

Solve for x: 0=x-1/(x^2)

The solution is x=1,x=-1/2+(sqrt(3))/2 i,x=-1/2-(sqrt(3))/2 i

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0 = x - \frac{1}{x ^{2}}

x = 1, x = - \frac{1}{2} + \frac{3}{2} i, x = - \frac{1}{2} - \frac{3}{2} i

Solution steps

0 = x - \frac{1}{x ^{2}}

Multiply both sides by

x^{2}

0 = x^{3} - 1

Solve

0 = x^{3} - 1 : x = 1, x = - \frac{1}{2} + \frac{3}{2} i, x = - \frac{1}{2} - \frac{3}{2} i

x = 1, x = - \frac{1}{2} + \frac{3}{2} i, x = - \frac{1}{2} - \frac{3}{2} i

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = 1, x = - \frac{1}{2} + \frac{3}{2} i, x = - \frac{1}{2} - \frac{3}{2} i

\frac{5 x + 2}{x + 2} = (7)

\frac{1}{x - 6} = \frac{3}{12 x}

\frac{- x}{3 - x} = \frac{5}{12}

\frac{x}{- 2 ( x + 3 )} = - 2 x - 6

\frac{1}{v + 6} = 4

What is the answer to 0=x-1/(x^2) ?
The answer to 0=x-1/(x^2) is x=1,x=-1/2+(sqrt(3))/2 i,x=-1/2-(sqrt(3))/2 i
Solve for x: 0=x-1/(x^2)
The solution is x=1,x=-1/2+(sqrt(3))/2 i,x=-1/2-(sqrt(3))/2 i