What is the answer to (2x^2+8x)/(3x+12)=-4 ?

The answer to (2x^2+8x)/(3x+12)=-4 is x=-6

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(2x^2+8x)/(3x+12)=-4

\frac{2 x ^{2} + 8 x}{3 x + 12} = - 4

x = - 6

Solution steps

\frac{2 x ^{2} + 8 x}{3 x + 12} = - 4

Simplify

\frac{2 x ^{2} + 8 x}{3 x + 12} : \frac{2 x}{3}

\frac{2 x}{3} = - 4

Multiply both sides by

3

2 x = - 12

Divide both sides by

2

x = - 6

Verify Solutions

Find undefined (singularity) points:

x = - 4

Combine undefined points with solutions:

x = - 6

2 - (y - 7)^{- 1} = 6 (y - 7)^{- 2}

18.06 = \frac{x ^{2}}{x + 1}

\frac{- 2}{c} = 2

f^{- 1} (- 2) = - 2 + 3

\frac{9 - x ^{2}}{x ^{2} + 3 x} = 0

What is the answer to (2x^2+8x)/(3x+12)=-4 ?
The answer to (2x^2+8x)/(3x+12)=-4 is x=-6
Solve for x: (2x^2+8x)/(3x+12)=-4
The solution is x=-6