What is the answer to ((2x+1)(x-1))/((x+1))=0 ?

The answer to ((2x+1)(x-1))/((x+1))=0 is x=-1/2 ,x=1

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((2x+1)(x-1))/((x+1))=0

\frac{( 2 x + 1 ) ( x - 1 )}{( x + 1 )} = 0

x = - \frac{1}{2}, x = 1

Decimal Notation

x = - 0.5, x = 1

Solution steps

\frac{( 2 x + 1 ) ( x - 1 )}{( x + 1 )} = 0

Simplify

\frac{( 2 x + 1 ) ( x - 1 )}{( x + 1 )} : \frac{( 2 x + 1 ) ( x - 1 )}{x + 1}

\frac{( 2 x + 1 ) ( x - 1 )}{x + 1} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

(2 x + 1) (x - 1) = 0

Solve

(2 x + 1) (x - 1) = 0 : x = - \frac{1}{2}, x = 1

x = - \frac{1}{2}, x = 1

Verify Solutions

Find undefined (singularity) points:

x = - 1

Combine undefined points with solutions:

x = - \frac{1}{2}, x = 1

\frac{6}{12} = \frac{2}{n}

a, hb + 5 = \frac{- b}{2 a}

2 x - 4 x^{- 1} = 7

x^{2} + \frac{5}{x ^{2}} = 6

\frac{9}{10} = \frac{7}{x}

What is the answer to ((2x+1)(x-1))/((x+1))=0 ?
The answer to ((2x+1)(x-1))/((x+1))=0 is x=-1/2 ,x=1
Solve for x: ((2x+1)(x-1))/((x+1))=0
The solution is x=-1/2 ,x=1