What is the answer to |x+4|+|x-7|=|2x-1| ?

The answer to |x+4|+|x-7|=|2x-1| is x=6

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|x+4|+|x-7|=|2x-1|

∣ x + 4 ∣ + ∣ x - 7 ∣ = ∣ 2 x - 1 ∣

x = 6

Solution steps

∣ x + 4 ∣ + ∣ x - 7 ∣ = ∣ 2 x - 1 ∣

Find positive and negative intervals

x < - 4, - 4 \leq x < \frac{1}{2}, \frac{1}{2} \leq x < 7, x \geq 7

Solve the inequality for each interval

No Solution or x = 6

x = 6

16 y (2 - y) + (4 y - 5)^{2} = 0

(x - 1) (x + 2) (x - 3) > 0

- (- x y^{2} z^{3})^{5} (x^{4} yz)^{2}

x^{2} = 4 x - 9

10 x^{5} y + 2 x^{3} y^{2} + 14 x^{2} y^{4}

What is the answer to |x+4|+|x-7|=|2x-1| ?
The answer to |x+4|+|x-7|=|2x-1| is x=6
Solve for x: |x+4|+|x-7|=|2x-1|
The solution is x=6