What is the answer to ((ax+b))/(cx+d)=2 ?

The answer to ((ax+b))/(cx+d)=2 is x=(2d-b)/(a-2c);\quad a\ne 2c

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((ax+b))/(cx+d)=2

\frac{( a x + b )}{c x + d} = 2

x = \frac{2 d - b}{a - 2 c}; a \neq = 2 c

Solution steps

\frac{( a x + b )}{c x + d} = 2

Simplify

\frac{( a x + b )}{c x + d} : \frac{a x + b}{c x + d}

\frac{a x + b}{c x + d} = 2

Multiply both sides by

c x + d

a x + b = 2 (c x + d)

Expand

2 (c x + d) : 2 c x + 2 d

a x + b = 2 c x + 2 d

Move

b

to the right side

a x = 2 c x + 2 d - b

Move

2 c x

to the left side

a x - 2 c x = 2 d - b

Factor

a x - 2 c x : x (a - 2 c)

x (a - 2 c) = 2 d - b

Divide both sides by

a - 2 c; a \neq = 2 c

x = \frac{2 d - b}{a - 2 c}; a \neq = 2 c

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1 - \frac{8}{3 x} = \frac{5}{3}

g, M = \frac{2 f g}{g - c}

\frac{2 x}{1 - x} = 55.3

v, f = \frac{v}{v - w} k

What is the answer to ((ax+b))/(cx+d)=2 ?
The answer to ((ax+b))/(cx+d)=2 is x=(2d-b)/(a-2c);\quad a\ne 2c