What are the solutions to the equation 25y^2-81=0 ?

The solutions to the equation 25y^2-81=0 are y= 9/5 ,y=-9/5

Find the zeros of 25y^2-81=0

The zeros of 25y^2-81=0 are y= 9/5 ,y=-9/5

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25 y^{2} - 81 = 0

y = \frac{9}{5}, y = - \frac{9}{5}

Decimal Notation

y = 1.8, y = - 1.8

Solution steps

25 y^{2} - 81 = 0

Move

81

to the right side

25 y^{2} = 81

Divide both sides by

25

y^{2} = \frac{81}{25}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = \frac{81}{25}, y = - \frac{81}{25}

\frac{81}{25} = \frac{9}{5}

- \frac{81}{25} = - \frac{9}{5}

y = \frac{9}{5}, y = - \frac{9}{5}

5 \geq \frac{1}{5} (- 10) - 5

(x - 6)^{2} = 20 - 2 x

(\frac{a}{b ^{3}})^{4}

(- 243)^{\frac{4}{5}}

- x^{2} \cdot x

What are the solutions to the equation 25y^2-81=0 ?
The solutions to the equation 25y^2-81=0 are y= 9/5 ,y=-9/5
Find the zeros of 25y^2-81=0
The zeros of 25y^2-81=0 are y= 9/5 ,y=-9/5