What is the answer to (y+3)/(y-4)=(3y)/(y+1) ?

The answer to (y+3)/(y-4)=(3y)/(y+1) is y=-(-8+sqrt(70))/2 ,y=(8+sqrt(70))/2

Solve for y: (y+3)/(y-4)=(3y)/(y+1)

The solution is y=-(-8+sqrt(70))/2 ,y=(8+sqrt(70))/2

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\frac{y + 3}{y - 4} = \frac{3 y}{y + 1}

y = - \frac{- 8 + 70}{2}, y = \frac{8 + 70}{2}

Decimal Notation

y = - 0.18330 \dots, y = 8.18330 \dots

Solution steps

\frac{y + 3}{y - 4} = \frac{3 y}{y + 1}

Cross multiply

(y + 3) (y + 1) = (y - 4) \cdot 3 y

Solve

(y + 3) (y + 1) = (y - 4) \cdot 3 y : y = - \frac{- 8 + 70}{2}, y = \frac{8 + 70}{2}

y = - \frac{- 8 + 70}{2}, y = \frac{8 + 70}{2}

Verify Solutions

Find undefined (singularity) points:

y = 4, y = - 1

Combine undefined points with solutions:

y = - \frac{- 8 + 70}{2}, y = \frac{8 + 70}{2}

\frac{x}{x + 1} = 1 - \frac{1}{x + 1}

v, t = \frac{d}{v}

\frac{2}{x} = \frac{18}{x ^{3}}

156 = \frac{180 ( n - 2 )}{n}

\frac{2}{v} = \frac{1}{8}

What is the answer to (y+3)/(y-4)=(3y)/(y+1) ?
The answer to (y+3)/(y-4)=(3y)/(y+1) is y=-(-8+sqrt(70))/2 ,y=(8+sqrt(70))/2
Solve for y: (y+3)/(y-4)=(3y)/(y+1)
The solution is y=-(-8+sqrt(70))/2 ,y=(8+sqrt(70))/2