What is the answer to 1-x/(x+2)= x/(x-3) ?

The answer to 1-x/(x+2)= x/(x-3) is x=sqrt(6)i,x=-sqrt(6)i

Solve for x: 1-x/(x+2)= x/(x-3)

The solution is x=sqrt(6)i,x=-sqrt(6)i

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1 - \frac{x}{x + 2} = \frac{x}{x - 3}

x = 6 i, x = - 6 i

Solution steps

1 - \frac{x}{x + 2} = \frac{x}{x - 3}

Multiply by LCM

(x + 2) (x - 3) - x (x - 3) = x (x + 2)

Solve

(x + 2) (x - 3) - x (x - 3) = x (x + 2) : x = 6 i, x = - 6 i

x = 6 i, x = - 6 i

2 - \frac{1}{x} = 1.1

\frac{x}{x - 2} = \frac{( 2 x - 3 )}{x}

\frac{10}{3} = \frac{4}{x} + 2

x, \frac{2}{x} = 3 + y

v, 13.51 = \frac{125}{v}

What is the answer to 1-x/(x+2)= x/(x-3) ?
The answer to 1-x/(x+2)= x/(x-3) is x=sqrt(6)i,x=-sqrt(6)i
Solve for x: 1-x/(x+2)= x/(x-3)
The solution is x=sqrt(6)i,x=-sqrt(6)i