What is the answer to (x^3-8)/(x^2+1)=0 ?

The answer to (x^3-8)/(x^2+1)=0 is x=2,x=-1+sqrt(3)i,x=-1-sqrt(3)i

Solve for x: (x^3-8)/(x^2+1)=0

The solution is x=2,x=-1+sqrt(3)i,x=-1-sqrt(3)i

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\frac{x ^{3} - 8}{x ^{2} + 1} = 0

x = 2, x = - 1 + 3 i, x = - 1 - 3 i

Solution steps

\frac{x ^{3} - 8}{x ^{2} + 1} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

x^{3} - 8 = 0

Solve

x^{3} - 8 = 0 : x = 2, x = - 1 + 3 i, x = - 1 - 3 i

x = 2, x = - 1 + 3 i, x = - 1 - 3 i

1.37 = \frac{12.85}{x}

\frac{1}{x - 1} - \frac{2}{x - 4} = 1

\frac{2}{x - 4} = \frac{6}{x - 6}

\frac{30}{x} + 3 = - \frac{9}{2}

- \frac{128000}{x ^{2}} + 2 x = 0

What is the answer to (x^3-8)/(x^2+1)=0 ?
The answer to (x^3-8)/(x^2+1)=0 is x=2,x=-1+sqrt(3)i,x=-1-sqrt(3)i
Solve for x: (x^3-8)/(x^2+1)=0
The solution is x=2,x=-1+sqrt(3)i,x=-1-sqrt(3)i