What is the answer to (3x(4-x)-1)/(2-24-x)=0 ?

The answer to (3x(4-x)-1)/(2-24-x)=0 is x=(6-sqrt(33))/3 ,x=(6+sqrt(33))/3

Solve for x: (3x(4-x)-1)/(2-24-x)=0

The solution is x=(6-sqrt(33))/3 ,x=(6+sqrt(33))/3

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\frac{3 x ( 4 - x ) - 1}{2 - 24 - x} = 0

x = \frac{6 - 33}{3}, x = \frac{6 + 33}{3}

Decimal Notation

x = 0.08514 \dots, x = 3.91485 \dots

Solution steps

\frac{3 x ( 4 - x ) - 1}{2 - 24 - x} = 0

Simplify

\frac{3 x ( 4 - x ) - 1}{2 - 24 - x} : \frac{3 x ( 4 - x ) - 1}{- x - 22}

\frac{3 x ( 4 - x ) - 1}{- x - 22} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

3 x (4 - x) - 1 = 0

Solve

3 x (4 - x) - 1 = 0 : x = \frac{6 - 33}{3}, x = \frac{6 + 33}{3}

x = \frac{6 - 33}{3}, x = \frac{6 + 33}{3}

Verify Solutions

Find undefined (singularity) points:

x = - 22

Combine undefined points with solutions:

x = \frac{6 - 33}{3}, x = \frac{6 + 33}{3}

\frac{4}{6} = \frac{n - 7}{n - 9}

\frac{4}{x - 3} = \frac{2}{5 - x}

\frac{( n + 1 ) !}{( n - 2 ) !} = n^{3} - n

5 x^{- 2} - 9 x^{- 1} - 2 = 0

a, b + \frac{m}{a} = z

What is the answer to (3x(4-x)-1)/(2-24-x)=0 ?
The answer to (3x(4-x)-1)/(2-24-x)=0 is x=(6-sqrt(33))/3 ,x=(6+sqrt(33))/3
Solve for x: (3x(4-x)-1)/(2-24-x)=0
The solution is x=(6-sqrt(33))/3 ,x=(6+sqrt(33))/3