What is the answer to 1.62*1+x=(1.8)/(1-x) ?

The answer to 1.62*1+x=(1.8)/(1-x) is x=-31/100-i(sqrt(839))/(100),x=-31/100+i(sqrt(839))/(100)

Solve for x: 1.62*1+x=(1.8)/(1-x)

The solution is x=-31/100-i(sqrt(839))/(100),x=-31/100+i(sqrt(839))/(100)

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1.62 \cdot 1 + x = \frac{1.8}{1 - x}

x = - \frac{31}{100} - i \frac{839}{100}, x = - \frac{31}{100} + i \frac{839}{100}

Solution steps

1.62 \cdot 1 + x = \frac{1.8}{1 - x}

Multiply both sides by

100

162 + 100 x = \frac{180}{1 - x}

Multiply both sides by

1 - x

162 (1 - x) + 100 x (1 - x) = 180

Solve

162 (1 - x) + 100 x (1 - x) = 180 : x = - \frac{31}{100} - i \frac{839}{100}, x = - \frac{31}{100} + i \frac{839}{100}

x = - \frac{31}{100} - i \frac{839}{100}, x = - \frac{31}{100} + i \frac{839}{100}

b^{- 1} = 5

\frac{5}{x} + 5 = 5

(x + 10) (\frac{1000}{x} - 5) = 1000

\frac{4}{v - 10} = \frac{11}{12}

\frac{1.5}{4.5} = \frac{3.5}{x}

What is the answer to 1.62*1+x=(1.8)/(1-x) ?
The answer to 1.62*1+x=(1.8)/(1-x) is x=-31/100-i(sqrt(839))/(100),x=-31/100+i(sqrt(839))/(100)
Solve for x: 1.62*1+x=(1.8)/(1-x)
The solution is x=-31/100-i(sqrt(839))/(100),x=-31/100+i(sqrt(839))/(100)