What is the answer to (x+1)(1+1/(x+3))x=0 ?

The answer to (x+1)(1+1/(x+3))x=0 is x=0,x=-1,x=-4

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(x+1)(1+1/(x+3))x=0

(x + 1) (1 + \frac{1}{x + 3}) x = 0

x = 0, x = - 1, x = - 4

Solution steps

(x + 1) (1 + \frac{1}{x + 3}) x = 0

Expand

(x + 1) (1 + \frac{1}{x + 3}) x : \frac{x ^{3} + 5 x ^{2} + 4 x}{x + 3}

\frac{x ^{3} + 5 x ^{2} + 4 x}{x + 3} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

x^{3} + 5 x^{2} + 4 x = 0

Solve

x^{3} + 5 x^{2} + 4 x = 0 : x = 0, x = - 1, x = - 4

x = 0, x = - 1, x = - 4

Verify Solutions

Find undefined (singularity) points:

x = - 3

Combine undefined points with solutions:

x = 0, x = - 1, x = - 4

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\frac{a}{a + 6} = \frac{2}{5}

x + \frac{3 x}{x + 2} = 2

\frac{18}{7} = \frac{22}{x}

\frac{8}{4 x - 8} - 1 = \frac{2}{x - 2}

What is the answer to (x+1)(1+1/(x+3))x=0 ?
The answer to (x+1)(1+1/(x+3))x=0 is x=0,x=-1,x=-4
Solve for x: (x+1)(1+1/(x+3))x=0
The solution is x=0,x=-1,x=-4