What is the answer to 4x^2+x^{-1}-3=0 ?

The answer to 4x^2+x^{-1}-3=0 is x=-1,x= 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4x^2+x^{-1}-3=0

4 x^{2} + x^{- 1} - 3 = 0

x = - 1, x = \frac{1}{2}

Decimal Notation

x = - 1, x = 0.5

Solution steps

4 x^{2} + x^{- 1} - 3 = 0

Refine

4 x^{2} + \frac{1}{x} - 3 = 0

Multiply both sides by

x

4 x^{3} + 1 - 3 x = 0

Solve

4 x^{3} + 1 - 3 x = 0 : x = - 1, x = \frac{1}{2}

x = - 1, x = \frac{1}{2}

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = - 1, x = \frac{1}{2}

\frac{x}{x + 4} + \frac{4}{x + 4} = - 2

4 - \frac{8000}{x ^{2}} = 0

\frac{2 x}{3} + \frac{3}{2 x} = 1

\frac{27}{x} + 41 = 50

\frac{25}{3 x} = \frac{2}{77}

What is the answer to 4x^2+x^{-1}-3=0 ?
The answer to 4x^2+x^{-1}-3=0 is x=-1,x= 1/2
Solve for x: 4x^2+x^{-1}-3=0
The solution is x=-1,x= 1/2