What is the answer to ((x^2-4x-5))/(x^2+1)=0 ?

The answer to ((x^2-4x-5))/(x^2+1)=0 is x=5,x=-1

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((x^2-4x-5))/(x^2+1)=0

\frac{( x ^{2} - 4 x - 5 )}{x ^{2} + 1} = 0

x = 5, x = - 1

Solution steps

\frac{( x ^{2} - 4 x - 5 )}{x ^{2} + 1} = 0

Simplify

\frac{( x ^{2} - 4 x - 5 )}{x ^{2} + 1} : \frac{x ^{2} - 4 x - 5}{x ^{2} + 1}

\frac{x ^{2} - 4 x - 5}{x ^{2} + 1} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

x^{2} - 4 x - 5 = 0

Solve

x^{2} - 4 x - 5 = 0 : x = 5, x = - 1

x = 5, x = - 1

\frac{1}{x + 4} = 2

x - \frac{9}{x + 4} = \frac{4 x}{x + 4}

\frac{12}{x + 2} = \frac{9}{x + 5}

15 - \frac{12}{x} = - 33

\frac{x}{x - 6} + 1 = \frac{6}{x - 6}

What is the answer to ((x^2-4x-5))/(x^2+1)=0 ?
The answer to ((x^2-4x-5))/(x^2+1)=0 is x=5,x=-1
Solve for x: ((x^2-4x-5))/(x^2+1)=0
The solution is x=5,x=-1