What is the answer to 7/(c+7)=(10)/(t-10) ?

The answer to 7/(c+7)=(10)/(t-10) is t=((c+7)*10)/7+10;\quad c\ne-7

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7/(c+7)=(10)/(t-10)

\frac{7}{c + 7} = \frac{10}{t - 10}

t = \frac{( c + 7 ) \cdot 10}{7} + 10; c \neq = - 7

Solution steps

\frac{7}{c + 7} = \frac{10}{t - 10}

Cross multiply

7 (t - 10) = (c + 7) \cdot 10

Divide both sides by

7

t - 10 = \frac{( c + 7 ) \cdot 10}{7}

Move

10

to the right side

t = \frac{( c + 7 ) \cdot 10}{7} + 10; c \neq = - 7

0.52 = \frac{x}{( x + 8 )}

0.9 = \frac{30}{x ^{2}}

0.5 = \frac{23 ( x - 1 )}{23 + 1000 x}

\frac{8}{5 x + 4} - \frac{1}{x - 4} = 0

x, \frac{y + x}{y - x} = 3

What is the answer to 7/(c+7)=(10)/(t-10) ?
The answer to 7/(c+7)=(10)/(t-10) is t=((c+7)*10)/7+10;\quad c\ne-7