What are the solutions to the equation 1/4 y^2+y+1=1 ?

The solutions to the equation 1/4 y^2+y+1=1 are y=0,y=-4

Find the zeros of 1/4 y^2+y+1=1

The zeros of 1/4 y^2+y+1=1 are y=0,y=-4

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\frac{1}{4} y^{2} + y + 1 = 1

y = 0, y = - 4

Solution steps

\frac{1}{4} y^{2} + y + 1 = 1

Multiply both sides by

4

y^{2} + 4 y + 4 = 4

Move

4

to the left side

y^{2} + 4 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 0 = 4

y_{1, 2} = \frac{- 4 \pm 4}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 4 + 4}{2 \cdot 1}, y_{2} = \frac{- 4 - 4}{2 \cdot 1}

y = \frac{- 4 + 4}{2 \cdot 1} : 0

y = \frac{- 4 - 4}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

y = 0, y = - 4

- 3 a - 9 = - (a + 7)

4 x + 15 = x + 3

8 x^{2} - 4 x = 18

(21 + 2 i) + (13 + 8 i)

4 m^{4} - 324

What are the solutions to the equation 1/4 y^2+y+1=1 ?
The solutions to the equation 1/4 y^2+y+1=1 are y=0,y=-4
Find the zeros of 1/4 y^2+y+1=1
The zeros of 1/4 y^2+y+1=1 are y=0,y=-4