What is the answer to 0=(2t^2)/(t+1)-15 ?

The answer to 0=(2t^2)/(t+1)-15 is t=(15+sqrt(345))/4 ,t=(15-sqrt(345))/4

Solve for t: 0=(2t^2)/(t+1)-15

The solution is t=(15+sqrt(345))/4 ,t=(15-sqrt(345))/4

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0 = \frac{2 t ^{2}}{t + 1} - 15

t = \frac{15 + 345}{4}, t = \frac{15 - 345}{4}

Decimal Notation

t = 8.39354 \dots, t = - 0.89354 \dots

Solution steps

0 = \frac{2 t ^{2}}{t + 1} - 15

Move

15

to the left side

15 = \frac{2 t ^{2}}{t + 1}

Multiply both sides by

t + 1

15 (t + 1) = 2 t^{2}

Solve

15 (t + 1) = 2 t^{2} : t = \frac{15 + 345}{4}, t = \frac{15 - 345}{4}

t = \frac{15 + 345}{4}, t = \frac{15 - 345}{4}

Verify Solutions

Find undefined (singularity) points:

t = - 1

Combine undefined points with solutions:

t = \frac{15 + 345}{4}, t = \frac{15 - 345}{4}

\frac{3 + 2 x}{3 - 2 x} = - 3

y, - y^{- 1} = - x^{2} + 3

\frac{2}{5} = \frac{30}{3 t + 9}

0 = \frac{1}{x ^{2} - 9}

4 π r - \frac{2000}{r ^{2}} = 0

What is the answer to 0=(2t^2)/(t+1)-15 ?
The answer to 0=(2t^2)/(t+1)-15 is t=(15+sqrt(345))/4 ,t=(15-sqrt(345))/4
Solve for t: 0=(2t^2)/(t+1)-15
The solution is t=(15+sqrt(345))/4 ,t=(15-sqrt(345))/4