What is the answer to B=((x^2+6))/((x^2+2)) ?

The answer to B=((x^2+6))/((x^2+2)) is x=sqrt((6-2B)/(B-1)),x=-sqrt((6-2B)/(B-1));\quad B\ne 1

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B=((x^2+6))/((x^2+2))

B = \frac{( x ^{2} + 6 )}{( x ^{2} + 2 )}

x = \frac{6 - 2 B}{B - 1}, x = - \frac{6 - 2 B}{B - 1}; B \neq = 1

Solution steps

B = \frac{( x ^{2} + 6 )}{( x ^{2} + 2 )}

Simplify

\frac{( x ^{2} + 6 )}{( x ^{2} + 2 )} : \frac{x ^{2} + 6}{x ^{2} + 2}

B = \frac{x ^{2} + 6}{x ^{2} + 2}

Multiply both sides by

x^{2} + 2

B (x^{2} + 2) = x^{2} + 6

Solve

B (x^{2} + 2) = x^{2} + 6 : x = \frac{6 - 2 B}{B - 1}, x = - \frac{6 - 2 B}{B - 1}; B \neq = 1

x = \frac{6 - 2 B}{B - 1}, x = - \frac{6 - 2 B}{B - 1}; B \neq = 1

- \frac{5}{( x - 2 ) ^{2}} = 0

\frac{1}{x - 1} = x + 1

\frac{x - 6}{x - 2} = - \frac{9}{x}

\frac{8}{3 x} = 1

\frac{3}{x - 1} - \frac{8}{x + 2} = 1

What is the answer to B=((x^2+6))/((x^2+2)) ?
The answer to B=((x^2+6))/((x^2+2)) is x=sqrt((6-2B)/(B-1)),x=-sqrt((6-2B)/(B-1));\quad B\ne 1