What are the solutions to the equation x^2-8x+18=0 ?

The solutions to the equation x^2-8x+18=0 are x=4+sqrt(2)i,x=4-sqrt(2)i

Find the zeros of x^2-8x+18=0

The zeros of x^2-8x+18=0 are x=4+sqrt(2)i,x=4-sqrt(2)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 8 x + 18 = 0

x = 4 + 2 i, x = 4 - 2 i

Solution steps

x^{2} - 8 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

Simplify

(- 8)^{2} - 4 \cdot 1 \cdot 18 : 22 i

x_{1, 2} = \frac{- ( - 8 ) \pm 2 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 2 i}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2 2 i}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2 2 i}{2 \cdot 1} : 4 + 2 i

x = \frac{- ( - 8 ) - 2 2 i}{2 \cdot 1} : 4 - 2 i

The solutions to the quadratic equation are:

x = 4 + 2 i, x = 4 - 2 i

2 n^{2} + 15 n + 7

- 14 m - 7 m + 1 = - 7 m + 1

12 x^{4} + 30 x^{3} + 18 x^{2}

(\frac{1}{64})^{c - 2} < 3 2^{2 c}

- (\frac{2}{3} a - \frac{1}{3}) + \frac{5}{3} a = - 4

What are the solutions to the equation x^2-8x+18=0 ?
The solutions to the equation x^2-8x+18=0 are x=4+sqrt(2)i,x=4-sqrt(2)i
Find the zeros of x^2-8x+18=0
The zeros of x^2-8x+18=0 are x=4+sqrt(2)i,x=4-sqrt(2)i