What is the answer to (x^2+4x-1)/((x+2)^2)=0 ?

The answer to (x^2+4x-1)/((x+2)^2)=0 is x=-2+sqrt(5),x=-2-sqrt(5)

Solve for x: (x^2+4x-1)/((x+2)^2)=0

The solution is x=-2+sqrt(5),x=-2-sqrt(5)

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\frac{x ^{2} + 4 x - 1}{( x + 2 ) ^{2}} = 0

x = - 2 + 5, x = - 2 - 5

Decimal Notation

x = 0.23606 \dots, x = - 4.23606 \dots

Solution steps

\frac{x ^{2} + 4 x - 1}{( x + 2 ) ^{2}} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

x^{2} + 4 x - 1 = 0

Solve

x^{2} + 4 x - 1 = 0 : x = - 2 + 5, x = - 2 - 5

x = - 2 + 5, x = - 2 - 5

Verify Solutions

Find undefined (singularity) points:

x = - 2

Combine undefined points with solutions:

x = - 2 + 5, x = - 2 - 5

1 - x - \frac{24}{72 x + 12} = 0

- \frac{x}{x + 6} - 1 = \frac{6}{x + 6}

- 2 = \frac{1}{1 + c}

\frac{17}{8} = \frac{9}{x}

\frac{1}{x} + \frac{1}{x - 1} = 3

What is the answer to (x^2+4x-1)/((x+2)^2)=0 ?
The answer to (x^2+4x-1)/((x+2)^2)=0 is x=-2+sqrt(5),x=-2-sqrt(5)
Solve for x: (x^2+4x-1)/((x+2)^2)=0
The solution is x=-2+sqrt(5),x=-2-sqrt(5)