What is the answer to (-180)/(x^2)+40x=0 ?

The answer to (-180)/(x^2)+40x=0 is

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(-180)/(x^2)+40x=0

\frac{- 180}{x ^{2}} + 40 x = 0

Solution steps

\frac{- 180}{x ^{2}} + 40 x = 0

Simplify

\frac{- 180}{x ^{2}} : - \frac{180}{x ^{2}}

- \frac{180}{x ^{2}} + 40 x = 0

Multiply both sides by

x^{2}

- 180 + 40 x^{3} = 0

Solve

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

\frac{x}{8} = \frac{10}{x}

\frac{1}{n} - \frac{1}{n + 1} = 0.05

10 = \frac{15}{X}

2 = \frac{1}{1 + c e ^{- 1}}

x = 4 + \frac{1}{1 + \frac{1}{x}}