What is the answer to solvefor k,c= k/(n(1-k)) ?

The answer to solvefor k,c= k/(n(1-k)) is k=(nc)/(nc+1);\quad c\ne-1/n

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor k,c= k/(n(1-k))

solve for

k, c = \frac{k}{n ( 1 - k )}

k = \frac{n c}{n c + 1}; c \neq = - \frac{1}{n}

Solution steps

c = \frac{k}{n ( 1 - k )}

Multiply both sides by

n (1 - k)

c n (1 - k) = k

Expand

c n (1 - k) : n c - kn c

n c - kn c = k

Move

n c

to the right side

- kn c = k - n c

Move

k

to the left side

- kn c - k = - n c

Factor

- kn c - k : - k (n c + 1)

- k (n c + 1) = - n c

Divide both sides by

- (n c + 1); c \neq = - \frac{1}{n}

k = \frac{n c}{n c + 1}; c \neq = - \frac{1}{n}

\frac{12}{x - 1} - \frac{8}{x} = 2

\frac{x - 3}{2 x} + 1 = \frac{x + 2}{x}

\frac{x - 5}{x + 3} = \frac{3}{x}

L, \frac{V}{L W} = H

x^{- 2} + 9 x^{- 1} + 18 = 0

What is the answer to solvefor k,c= k/(n(1-k)) ?
The answer to solvefor k,c= k/(n(1-k)) is k=(nc)/(nc+1);\quad c\ne-1/n