What is the answer to ((x^2+x))/(x-1)=6 ?

The answer to ((x^2+x))/(x-1)=6 is x=3,x=2

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((x^2+x))/(x-1)=6

\frac{( x ^{2} + x )}{x - 1} = 6

x = 3, x = 2

Solution steps

\frac{( x ^{2} + x )}{x - 1} = 6

Simplify

\frac{( x ^{2} + x )}{x - 1} : \frac{x ^{2} + x}{x - 1}

\frac{x ^{2} + x}{x - 1} = 6

Multiply both sides by

x - 1

x^{2} + x = 6 (x - 1)

Solve

x^{2} + x = 6 (x - 1) : x = 3, x = 2

x = 3, x = 2

Verify Solutions

Find undefined (singularity) points:

x = 1

Combine undefined points with solutions:

x = 3, x = 2

x^{- 4} - 13 x^{- 2} + 36 = 0

\frac{1}{x} = \frac{3}{5 x}

y^{- 2} = \frac{25}{4}

x + (\frac{1}{x}) = 10

\frac{3}{x - 5} = \frac{2}{2 - x}

What is the answer to ((x^2+x))/(x-1)=6 ?
The answer to ((x^2+x))/(x-1)=6 is x=3,x=2
Solve for x: ((x^2+x))/(x-1)=6
The solution is x=3,x=2